x^2+7x=x^2-3x+40

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Solution for x^2+7x=x^2-3x+40 equation:


Simplifying
x2 + 7x = x2 + -3x + 40

Reorder the terms:
7x + x2 = x2 + -3x + 40

Reorder the terms:
7x + x2 = 40 + -3x + x2

Add '-1x2' to each side of the equation.
7x + x2 + -1x2 = 40 + -3x + x2 + -1x2

Combine like terms: x2 + -1x2 = 0
7x + 0 = 40 + -3x + x2 + -1x2
7x = 40 + -3x + x2 + -1x2

Combine like terms: x2 + -1x2 = 0
7x = 40 + -3x + 0
7x = 40 + -3x

Solving
7x = 40 + -3x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '3x' to each side of the equation.
7x + 3x = 40 + -3x + 3x

Combine like terms: 7x + 3x = 10x
10x = 40 + -3x + 3x

Combine like terms: -3x + 3x = 0
10x = 40 + 0
10x = 40

Divide each side by '10'.
x = 4

Simplifying
x = 4

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